a ball rolls from rest down in an incline with a uniform acceleration of 4ms

Cydel Terubea

what is its speed after 8sec?
how long will it take to reach a speed of 36ms?
how long does it take to travel a distance of 200m and what is its speed after going this direction?
how far does it travel during the third second of its motion?

v = u+a.t
U= initial velocity = 0
So v = a.t
a=4, t=8. Pop in the numbers and get the answer
Rearrange v=a.t to get
t =v/a
Velocity required = V = 36. a=4
Pop in the numbers and get the answer
For distance you have to use s=ut + 0.5a.(t.t) (t.t) = t squared
initial velocity u=0 so ut = 0
Rearrange to get
t = ????
Pop the numbers in to get the answer
To get the speed after that time, use v = a.t again as per the start of the question
Finally to get distance (s) travelled in the 3rd second, find out the speed at the start (t=2) of that second using the techniques above. That will be u, initial velocity for this part of the question.
Then use s=ut + 0.5 a(t.t) to get the distance, s.

Tabitha Farrant

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Kirk Bundles

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Kirk Bundles

Therefore there's is an equation about the 4ms, you must have to consider those terms that I have grabbed and allocated from the dissertation bliss - http://www.dissertationtbliss.co.uk/ as they provide me the equation details in my dissertation.
Displacement: The distance measured along a straight line in a stated direction w.r.t. the
original point (vector).
Velocity: Rate of change of displacement
Acceleration: Rate of change of velocity
Note: Negative Acceleration = Retardation

Mary  Patton

I agree with Mart Patton and Tabitha Farrant because both have given well detailed answers.

Ashley Sewell